Answer : The volume of gas sample will be, 9.93 L
Explanation :
Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.
Mathematically,
![(V_1)/(T_1)=(V_2)/(T_2)](https://img.qammunity.org/2021/formulas/physics/high-school/ed0g2x31neufjg9l8yqh2u42wst3fdwcfq.png)
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
![V_1=11.3L\\T_1=32^oC=(32+273)K=305K\\V_2=?\\T_2=-5^oC=(-5+273)K=268K](https://img.qammunity.org/2021/formulas/chemistry/high-school/slq1shj9a7uupgn6gvraoptp2o4jtz67uk.png)
Now put all the given values in above equation, we get:
![(11.3L)/(305K)=(V_2)/(268K)\\\\V_2=9.93L](https://img.qammunity.org/2021/formulas/chemistry/high-school/t4agj8tkjxwpium69ss6gfvtq39emzwami.png)
Therefore, the volume of gas sample will be, 9.93 L