Question

20.0 g of Nitrogen is produced when oxygen gas reacts with NO gas. 29.8 L of oxygen is required at STP to produce this 20.0 g of NO.

A.
True

B.
False

Answer 1

The statement is false as 85675 grams of nitrogen dioxide is produced instead of 20 grams.

Step-by-step explanation:

Balance equation for the reaction:

2NO +
`O_(2)` ⇒ 2N
`O_(2)`

Data given:

mass of nitrogen produced = 20 gram

mass of oxygen = 29.8 litres or 29800 grams

0xygen is the limiting reagent so,

number of moles of oxygen: (atomic mass of 1 mole 32 grams/mole

number of moles =
`(mass)/(atomic mass of 1 mole)`

putting the values in the equation:

=
`(29800)/(32)`

= 931.5 moles

1 mole of oxygen reacts to give 2 moles of NO2

931.5 moles of oxygen will give x moles

`(2)/(1)`=
`(x)/(931.5)`

1862.5 moles of NO2 produced

in grams

mass = number of moles x atomic mass

mass = 1862.5 x 46.00

= 85675 grams

The statement is false as 85675 grams of nitrogen dioxide is produced instead of 20 grams as said in question.