Question

PLEASE HELP ASAP!!!!

A 237-g piece of wire is heated, and the temperature of the wire changes from 25*C to 107*C. The amount of heat absorbed is 722 cal. What is the specific heat of the wire? Show all work, including the equation, and include units

Answer 1

The answer to your question is C = 0.037 cal/g°C

Step-by-step explanation:

Data

mass of the wire = m = 237 g

temperature 1 = T1 = 25°C

temperature 2 = T2 = 107°C

Heat = Q = 722 cal

Specific heat = C

Process

1.- Write the formula to find the specific heat

Q = mC(T2 - T1)

-Solve for C

C = Q / m(T2 - T1)

2.- Substitution

C = 722 / 237(107 - 25)

3.- Simplification

C = 722 / 237(82)

C = 722 / 19434

4.- Result

C = 0.037 cal/g°C