Answer: 103 litres
Step-by-step explanation:
Given that,
Original volume of fluorine gas (V1) = 95.8L
Original temperature of fluorine gas (T1) = 24.5°C
[Convert 24.5°C to Kelvin by adding 273
24.5°C + 273 = 297.5K]
New volume of gas (V2) = ?
New temperature of gas (T2) = 46.9°C
[Convert 46.9°C to Kelvin by adding 273
46.9°C + 273 = 319.9K]
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
95.8L/297.5K = V2/319.9K
To get the value of V2, cross multiply
95.8L x 319.9K = 297.5K x V2
30646.42L•K = 297.5K•V2
Divide both sides by 297.5K
30646.42L•K/297.5K = 297.5K•V2/297.5K
103L = V2
Thus, the new volume of fluorine gas will be 103 litres