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Anita sells stuffed bunnies and puppies to a toy store. She sells each bunny for $8.00 and each puppy for $10.00. This week, Anita wants to sell more than 30 stuffed animals and needs to earn a minimum of $450.

Which system of inequalities can Anita use to determine the number of stuffed bunnies, x, and stuffed puppies, y, that she can sell to meet her goals?

A. x + y > 30
8x + 10y ≥ 450

B. x + y > 30
8x + 10y ≤ 450

C. x + y < 30
8x + 10y ≥ 450

D. x + y < 30
8x + 10y ≤ 450

2 Answers

1 vote

Answer:

A. x + y > 30

8x + 10y ≥ 450

Explanation:

User Karega
by
3.0k points
3 votes

Answer:

A. x + y > 30

8x + 10y ≥ 450

Explanation:

x = bunnies

y = puppies

X + Y = more than 30 = X+Y >30

1 bunny equals $8.00

1 puppy equals $10.00

so, 8x + 10y= at least $450 = 8x + 10y ≥ $450

User Vitaliy Tsvayer
by
2.5k points