Question

Worth 45 points. Solve. 4k^2+12k+8

Answer 1

k = -1 and k = -2

Explanation:

We can use the quadratic formula, which says that for the quadratic
`ax^2+bx+c=0`, the solutions are: x =
`(-b+√(b^2-4ac) )/(2a)` or
`(-b-√(b^2-4ac) )/(2a)` .

Here, a = 4, b = 12, and c = 8, so: x =
`(-12+√(12^2-4*4*8) )/(2*4)` or
`(-12-√(12^2-4*4*8) )/(2*4)`.

Simplifying, we get k = -1 or k = -2.

Thus, k = -1 and -2.

Hope this helps!

Answer 2

k = -1, -2.

Explanation:

4k^2+12k+8 = 0

Divide by 4:

4(k^2 + 3x + 2) = 0

4(k + 1)(k + 2) = 0

k = -1, -2.