Final answer:
To solve the algebraic problem involving the ages of a dog and the student's friend, we set up the equation (D + 6) + 3 = 2(D + 3) and find that the dog is currently 3 years old.
Step-by-step explanation:
The student's question is a problem involving basic algebra where the ages of a dog and the student's friend are to be determined. Let's define the current age of the dog as D years old. The question says the dog is 6 years younger than the friend, so the friend's age can be represented as D + 6 years old. In 3 years, the friend will be twice as old as the dog, making the friend's age 2(D + 3) at that time. To determine the dog's current age, we set up the following equation:
Friend's age in 3 years = 2 times the dog's age in 3 years
(D + 6) + 3 = 2(D + 3)
We solve this equation step by step:
- Expand both sides:
D + 9 = 2D + 6 - Rearrange the equation to isolate D:
D = 3 (This is the current age of the dog.)
Therefore, the dog is currently 3 years old.