Question

What is the point-slope form of a line that has a slope of -4 and passes through point (-3, 1)?

O y-(-3)=-4(x-1)
O y-1 =-4[x-(-3)]
O-1-y,--4-3-x)
O 3-y, = -4(1-x)

Answer 1

Second choice:

`y-1=-4[x -(-3)]`

Step-by-step explanation:

The point-slope form of a line is:

`y-y_1=m(x-x_1)`

Where m is the slope and x₁, y₁ are the coordinates of any point that is on the line,

In this case, you are given:

• m = -4
• x₁ = -3
• y₁ = 1

Substituting in the point-slope form you get:

`y-1=-4[x -(-3)]`

Which is the second option.