What is the y-intercept, axis of symmetry and vertex of the following function. F(x)=-3x^(2) -6x-5 I will give brainilst help please

Question

What is the y-intercept, axis of symmetry and vertex of the following function.


`F(x)=-3x^(2) -6x-5`

I will give brainilst help please

Answer 1

Y intercept = 5
Axis of sym = -1
Vertex = (-1, -2)

Answer 2

To find the y intercept you must substitute 0 into x.

F(x) = (-3x0) - (6x0) - 5
F(x) = -5

To find the axis of symmetry and vertex we use the formula -b/2a to find the x coordinate

x = 6/(-3x2)
x = 6/-6
x = -1

Now we need to find the y coordinate so we sub -1 into x.

F(x) = (-3x-1) - (6x-1) - 5
F(x) = 3 + 6 - 5
F(x) = 4

The axis of symmetry and vertex are (-1,4) and the y coordinate is -5. Hope this helps.