Question

If 75.2 grams of Calcium Sulfate are reacted with an unlimited amount of Sodium Phosphate,

what mass of Calcium Phosphate will be formed according to the reaction:

Answer 1

55.83 grams is the mass of Calcium Phosphate will be formed according to the reaction when 75.2 grams of Calcium Sulfate are reacted with an unlimited amount of Sodium Phosphate.

Step-by-step explanation:

Data given:

mass of calcium sulphate reacted= 75.2 grams

atomic mass of calcium sulphate = 136.14 grams/mole

balanced chemical reaction equation:

3CaS
`O_(4)` +2
`Na_(3)` (P
`O_(4)`)
`_(2)` ⇒
`Ca_(3)` (P
`O_(4)`)
`_(2)` + 3
`Na_(2)`S
`O_(4)`

number of moles of calcium phosphate given will be calculated as:

number of moles =
`(mass)/(atomic mass of 1 mole)`

putting the values in the above formula, we get

number of moles =
`(75.2)/(136.4)`

= 0.55 moles of CaS
`O_(4)` is given

From the balanced equation:

3 moles of CaS
`O_(4)` reacts to give 1 mole of calcium phosphate

so, 0.55 moles of CaS
`O_(4)` will react to form x moles of calcium phosphate

`(1)/(3)` =
`(x)/(0.55)`

3x = 0.55

x = 0.18 moles of calcium phosphate is formed

mass = number of moles x atomic mass of calcium phosphate

(atomic mass of
`Ca_(3)`(P
`O_(4)`)
`{3}` =310.18 grams/mole)

putting the values in the formula:

mass = 0.18 x 310.18

= 55.83 grams of calcium phosphate is formed.