Question

If 36 columb of charge pass through a wire in 45 what is it carrying ​

Answer 1

`\qquad\qquad\huge\underline{{\sf Answer}}`

Here we go ~

`\qquad \tt \dashrightarrow \:Electric \: \: current = ( Charge )/(time)`

`\qquad \tt \dashrightarrow \:E= (36 )/(45)`

`\qquad \tt \dashrightarrow \:E= 0.8 \: \: amp`