Answer: 0.225 moles
Step-by-step explanation:
Calcium chloride has a chemical formula of CaCl2
Given that,
Amount of moles of CaCl2 (n) = ?
Volume of aqeous solution (v) = 500mL
[Convert volume in milliliters to liters
If 1000mL = 1L
500mL = Z
cross multiply
Z x 1000mL = 1L x 500mL
Z = 500mL•L / 1000mL
Z = 0.5L]
Concentration of CaCl2 solution (c) = 0.45M
Since concentration (c) is obtained by dividing the amount of solute dissolved by the volume of solvent, hence
c = n / v
make n the subject formula
n = c x v
n = 0.45M x 0.5L
n = 0.225 moles
Thus, 0.225 moles were required to prepare 500mL of a 0.45M calcium chloride solution