Answer:
t=64
Explanation:
L.C.M. of 2 and 3=6
![t^{(1)/(6) } =x\\squaring\\ t^{(1)/(3) } =x^(2) \\cubing\\t^{(1)/(2) } =x^(3) \\x^(2) +x^(3) =12\\when~ x=2\\2^2+2^3=4+8=12\\so~ x=2~ is~ one~ root.\\](https://img.qammunity.org/2021/formulas/mathematics/middle-school/255vi8txb1xwen1x1u0i0fw84uafajydcd.png)
By synthetic division.
2| 1 1 0 -12
| 2 6 12
-------------------
1 3 6|0
x²+3x+6=0
disc.=b²-4ac=3²-4×1×6=9-24=-15<0
so roots are imaginary.
x=2
![t^{(1)/(6) } =2\\t=2^6=64](https://img.qammunity.org/2021/formulas/mathematics/middle-school/90rw2m3bl8mk3cqxmhzee6yuvqo1ev9es5.png)
if the statement is as given by Sadievigil then he or she is correct otherwise refer to my solution.