Question

A piston has an initial volume of 1.643 L at a pressure of 128 kPa. The temperature is maintained at 27 oC as the volume is decreased to 0.593 L. What is the new pressure in kilopascals?

Answer 1

• 355 kPa

Step-by-step explanation:

The ideal gases follow Boyle's law: at constant temperature pressure and volume are inversely related:

`PV=constant`

`P_1V_1=P_2V_2`

`P_2=(P_1V_1)/(V_2)`

Subsituting and computing:

`P_2=(1.643L* 128kPa)/(0.593L)\approx355kPa`