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2x^2+x-1=2, What would the solutions be? I’ve been trying to solve this for a little now and I can’t seem to find the answers.

1 Answer

6 votes

Answer:

x = -3/2 x=1

Explanation:

2x^2+x-1=2

Subtract 2 from each side

2x^2+x-1-2=2-2

2x^2+x-3=0

Factor

(2x ) (x )

We will use -3 and 1 or -1 and 3 because we need -3 as the last term

2*1 -3 =-1 wrong we need 1

2 * -1 +3 =1 correct this will give us 1 as the middle term

The -1 goes on the outside and the +3 goes on the inside

(2x +3 ) (x -1) =0

Using the zero product property

2x+3 =0 x-1=0

2x = -3 x=1

x = -3/2 x=1

User Mark Beaton
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