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Can you pleaseeeee solve (x-5)^2=3

2 Answers

0 votes

Answer:


\huge\boxed{x=5-\sqrt3\ \vee\ x=5+\sqrt3}

Explanation:


(x-5)^2=3\iff x-5=\pm\sqrt3\qquad\text{add 5 to both sides}\\\\x-5+5=-\sqrt3+5\ \vee\ x-5+5=\sqrt3+5\\\\x=5-\sqrt3\ \vee\ x=5+\sqrt3

User Chhavi Gangwal
by
7.8k points
2 votes

Answer:

x = 5±sqrt(3)

Explanation:

(x-5)^2=3

Take the square root of each side

sqrt((x-5)^2)=±sqrt(3)

x-5 = ±sqrt(3)

Add 5 to each side

x-5 +5= 5±sqrt(3)

x = 5±sqrt(3)

User Chharvey
by
8.4k points

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