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How many milliliters of 0.60 H₂SO₄ are required to neutralize 90 mL of 0.40 NaOH?

1 Answer

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Answer:

The answer to your question is 30 ml of H₂SO₄

Step-by-step explanation:

Data

the volume of H₂SO₄ = ?

[H₂SO₄] = 0.6 M

volume of NaOH = 90 ml

[NaOH] = 0.4

Process

1.- Write the balanced chemical equation

H₂SO₄ + 2NaOH ⇒ Na₂SO₄ + 2H₂O

2.- Calculate the moles of NaOH

Molarity = moles/volume

moles = Molarity x volume

-Substitution

moles = 0.4 x 0.09

-result

moles = 0.036 of NaOH

3.- Calculate the moles of H₂SO₄

1 mol of H₂SO₄ ---------------- 2 moles of NaOH

x ----------------- 0.036 moles of NaOH

x = (0.036 x 1)/2

x = 0.018 moles of H₂SO₄

4.- Calculate the volume of H₂SO₄

Volume = moles / Molarity

-Substitution

Volume = 0.018 / 0.6

-Result

Volume = 0.03 ml or 30 ml

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