Question

Determine a general formula​ (or formulas) for the solutions to the following equation.​?

Then, determine the specific solutions​ (if any) on the interval ​[0,2pi).

cos theta= square root 3 divided by 2

Answer 1

Explanation:

`cos ~\theta=\frac{\sqrt {3}}{2}=cos ~(\pi )/(6),cos (2 \pi- (\pi )/(6))\\=cos (2k\pi +(\pi )/(6)),cos (2k\pi +(11\pi )/(6))\\\theta=2 k\pi +(\pi )/(6),or~\theta=2k\pi +(11\pi )/(6)\\for ~general~solution~put ~k=0\\\theta=(\pi )/(6)~\theta=(11\pi )/(6)`