The wavelength of the light that are not reflected in the air is,
λ5= 600 nm, λ6= 500 nm, λ7=428 nm.
Step-by-step explanation:
- For the above problem, we have the case as no<n1 and n2 < n1 .
- so we have(1<1.5;1.4<1.5)To find the wavelengths of the light that is not reflected in the air.
- Since the phase changes are not common on both the surfaces/
- we have the formula, λ=2d n²/m ( where m=1,2,3,4,5...)
- solving the problem we get,
- λ5= 600 nm, λ6= 500 nm, λ7=428 nm
- The wavelength of the light that are not reflected in the air is,
λ5= 600 nm, λ6= 500 nm, λ7=428 nm.