Question

The combustion of ethane

(
C
2
H
6
)
produces carbon dioxide and steam.

2
C
2
H
6
(
g
)
+
7
O
2
(
g
)
⟶
4
CO
2
(
g
)
+
6
H
2
O
(
g
)


How many moles of
CO
2
are produced when
5.35
mol
of ethane is burned in an excess of oxygen?

Answer 1

10.70 mol CO2

Step-by-step explanation:

This is the balanced reaction:

2C2H6 + 7O2 -----> 4CO2 + 6H2O

If given 5.35 moles of ethane to find the amount of carbon dioxide multiply by the ratio between CO2 and C2H6 (4:2 = 2:1). In our case we just need to double it.

mol CO2 = 5.35 * 2 = 10.70 mol CO2

Answer 2

10.7 moles

Step-by-step explanation:

Step 1:

The balanced equation for the reaction is given below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

Step 2:

Determination of the number of mole of ethane (C2H6) that reacted and the number of mole of CO2 produced from the balanced equation. This is shown below:

From the balanced equation,

Number of mole of C2H6 that reacted = 2 moles

Number of mole of CO2 produced = 4 moles.

Step 3:

Determination of the number of mole of CO2 produced by burning 5.35 mole of ethane (C2H6). This is illustrated below:

From the balanced equation above,

2 moles of C2H6 produced 4 moles of CO2.

Therefore, 5.35 moles of C2H6 will produce = (5.35 x 4)/2 = 10.7 moles of CO2.

From the calculations made above, 10.7 moles of CO2 will be produced when 5.35 moles of ethane (C2H6) is burned in excess oxygen