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Trigonometry, someone help me with this​

Trigonometry, someone help me with this​-example-1
User Markreyes
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\displaystyle\bf\\m(\sphericalangle~R)=30^o\\\\\implies~~(PQ)/(QR)=(1)/(2)\\\\QR=2*(4√(3))/(3)\\\\ \boxed{\bf~y=(8√(3))/(3)}\\\\\textbf{We use the Pythagorean theorem}\\\\PR=√(QR^2-PQ^2)=\sqrt{\left((8√(3))/(3)}\right)^2-\left((4√(3))/(3)}\right)^2}=\\\\\\=\sqrt{(64*3)/(9)-(16*3)/(9)}}=\sqrt{(64)/(3)-(16)/(3)}}= \sqrt{(64-16)/(3)}=\sqrt{(48)/(3)}=√(16)=4\\\\\\\boxed{\bf~x=4}

User Jakogut
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