Answer : The oxidation states of chlorine in these three ions
,
and
is, (+1), (+5) and (-1) respectively.
Explanation :
Oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.
Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.
When the atoms are present in their elemental state then the oxidation number will be zero.
Rules for Oxidation Numbers :
The oxidation number of a free element is always zero.
The oxidation number of a monatomic ion equals the charge of the ion.
The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
The oxidation number of oxygen (O) in compounds is usually -2, but it is -1 in peroxides.
The oxidation number of a Group 1 element in a compound is +1.
The oxidation number of a Group 2 element in a compound is +2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
The given ion is,
![ClO^-](https://img.qammunity.org/2021/formulas/chemistry/high-school/38cpnwdbz8mqmmsegpge8bdc8kkzdxnxw2.png)
Let the oxidation state of 'Cl' be, 'x'
![x+(-2)=-1\\\\x-2=-1\\\\x=-1+2\\\\x=+1](https://img.qammunity.org/2021/formulas/chemistry/high-school/w6c55uw3cqg7w2k4fx97yhi99th1i2co8l.png)
The oxidation number of chlorine in
is, (+1)
The given ion is,
![ClO_3^-](https://img.qammunity.org/2021/formulas/chemistry/high-school/ma12ep5gvzx370melnuyafuhen2vbvyr3c.png)
Let the oxidation state of 'Cl' be, 'x'
![x+3(-2)=-1\\\\x-6=-1\\\\x=-1+6\\\\x=+5](https://img.qammunity.org/2021/formulas/chemistry/high-school/xhae44eo9xu8sd07j6j7cxo1u3t07pr2iu.png)
The oxidation number of chlorine in
is, (+5)
The given ion is,
![Cl^-](https://img.qammunity.org/2021/formulas/chemistry/high-school/m3t9k8k38q4s6wouvyrh6evwkyfwq14lvw.png)
Let the oxidation state of 'Cl' be, 'x'
![x=-1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/r09d2j03o35wlqb201n202kkqkmlb1vt4x.png)
The oxidation number of chlorine in
is, (-1)