Question

A rolling pin has two identical cylindrical handles attached to a larger handle that is 12 inches long. The large cylinder measures 5 inches in diameter and the handles measure 1.5 inches in diameter. What is the volume of the rolling pin in cubic inches? Round to the nearest tenth

Answer 1

Volume of the rolling pin = 246.09
`in^(3)`

Explanation:

Length of larger cylinder L = 12 in

Diameter of larger cylinder D = 5 in

Diameter of two handles = 1.5 in

Length of two handles = 3 in

Volume of the rolling pin = Volume of two handles + Volume of larger cylinder

Volume of two handles = 2 (
`\pi r^(2)L`)

Volume of two handles = 2 (3.14 ×
`0.75^(2)` × 3 )

Volume of two handles = 10.59
`in^(3)`

Volume of larger cylinder = (
`\pi r^(2)L`)

Volume of larger cylinder = (3.14 ×
`2.5^(2)` × 12 )

Volume of larger cylinder = 235.5
`in^(3)`

Volume of the rolling pin = 10.59 + 235.5

Volume of the rolling pin = 246.09
`in^(3)`