Given:
The composite figure consists of a square and three semicircles.
Given that the half of the side of the square is 2 cm.
From the figure, the other half of the same side is also equal, then the side of the square is 2 + 2 = 4 cm.
We need to determine the area of the composite figure.
Area of the square:
The area of the square can be determined using the formula,
![A=s^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/o9zxg41yvoa3srjrnclaalypba9y5e71gu.png)
where s is the side length of the square.
Substituting s =4 ,we get;
![A=4^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ktfbldsm5kix09fwfa6kw77u774cj3tkwc.png)
![A=16](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9yenxcjxszwbyp7377zaf57mks3bxtkodb.png)
Thus, the area of the square is 16 cm²
Area of the semicircle:
The area of the semicircle can be determined using the formula,
![A=(\pi r^2)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/fwoczdfxj32sjqy8r4a04a843tv6kpa2j9.png)
The radius of the semicircle is 2 cm.
Substituting r = 2 in the above formula, we get;
![A=(\pi 4)/(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/swdhox6r1uxz172etpibgtg2hib1upc3sw.png)
![A=2 \pi](https://img.qammunity.org/2021/formulas/mathematics/middle-school/khewog6dov2lfygea1e8ivmvwgkgd00drk.png)
Thus, the area of the semicircle is 2π
Area of the composite figure:
The area of the composite figure can be determined by adding the area of the square and the three semicircles.
Thus, we have;
Area = Area of square + (3 × Area of semicircle)
Substituting the values, we have;
![Area = 16 +(3 * 2 \pi)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qgqvqo1ls1nhg86y0u12omwepz11bf0he4.png)
![Area = 16+6 \pi](https://img.qammunity.org/2021/formulas/mathematics/middle-school/gkenzr53ydflbhkehkjqzrrwjtmdmm7a0j.png)
Thus, the area of the composite figure is
![(6 \pi +16) \ cm^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/tug5ly3sfa0iynku4womvgq76us12kg4lm.png)
Hence, Option b is the correct answer.