Question

This is super hard i needd help

Answer 1

2587mm^3 approx!

Explanation:

first you divide the nut into 6 part(in triangle now, by joining centre to each edge)

let's take one part of the triangular shape then area of that part can be found by using 1/2×base×height

i.e, 1/2×13×15=97.5(mm^2)

now when we consider depth of that traingular part,we will get volume of that part as area×depth

i.e, 97.5×6=585(mm^3)

now volume of all the 6 triangular part is 585×6=3510(in mm^3)

now take circular cavity in consideration, it's volume will be π(7^2)6=923(mm^3) approximately

now reqired volume will be volume of that hexagonal part minus that of circular cavity

=3510-923

=2587mm^3

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