Question

On a coordinate plane, a line goes through (negative 4, 2) and (negative 2, negative 4). Which are solutions of the linear equation? Select all that apply. 3x + y = –10

Answer 1

The 2nd and last one

Explanation:

(-2,-4)

(-5,5)

I did it on edge 2020

Answer 2

Y = (-3) *X - 10

solution for Y =0 ---> X = -10/3

Explanation:

Two points:

(Y0 ; X0) = (-4 ; 2)

(Y1 ; X1) = (-2 ; -4)

There is only one line which pass for both of them, his general expresion is:

y = a*x + b --- (1)

Calculating "a": is the pending of the line.

`a = (Y1 - Y0)/(X1 - X0) = ((-4) - (2))/(-2 - (-4)) =(-6)/(2) = -3`

Calculating "b":

Since every point who belongs to the line satisfied the (1) expresion, we can use it for the point (Y1 ; X1) :

`Y0 = (-3)*X0 + b ---> 2 = (-3)*(-4) + b ---> b = -10`

Final expresion

Replacing in (1):
`Y = (-3) *X - 10`

Solutions:
`Y = (-3) *X - 10 = 0 --- > X = -(10)/(3)`