Question

The area of circle K when c=24x^2 pi

Answer 1

Answer:
`(√(6)√(\pi )√(Kc))/(12\pi ),\:x=-(√(6)√(\pi )√(Kc))/(12\pi )`

Explanation:

`c=24x^2 pi`

Switch sides:

`24x^2\pi =Kc`

divide both sides by
`24\pi`

`(24x^2\pi )/(24\pi )=(Kc)/(24\pi )`

simplify:

`x^2=(Kc)/(24\pi )`

`x^2=(Kc)/(24\pi )`
`x=\sqrt{(Kc)/(24\pi )},\:x=-\sqrt{(Kc)/(24\pi )}`

answer:
`x=(√(6)√(\pi )√(Kc))/(12\pi ),\:x=-(√(6)√(\pi )√(Kc))/(12\pi )`

i hope it's help!