Answer:
![8\text{ feet}](https://img.qammunity.org/2021/formulas/mathematics/high-school/48byzdx1sjvm7oxy284ajphh6b573i68a1.png)
Explanation:
GIVEN: A pool measuring
meters by
meters is surrounded by a path of uniform width. If the area of the pool and path combined is
square meters.
TO FIND: Width of the path.
SOLUTION:
Consider the figure attached.
let the width of the path be
![=x](https://img.qammunity.org/2021/formulas/mathematics/high-school/x4rn39ah9jn4y4hy4phqsd6gkq9n4qd916.png)
Total width of pool including pool
![=12+2x](https://img.qammunity.org/2021/formulas/mathematics/high-school/lyiwhwzv2ycu9e9t68xg0az5pdrbqbttjo.png)
Total length of pool including pool
![=30+2x](https://img.qammunity.org/2021/formulas/mathematics/high-school/idi75cqddgnbaxpjplq5o9e4r1ib4hnag4.png)
Now,
Area of pool and path combined
![=1288\text{ sq m}](https://img.qammunity.org/2021/formulas/mathematics/high-school/8yrlgbx6hdt2egqwrnni59gvbffiv9zfsu.png)
area of pool and path combined
![=(\text{length})*\text{width}](https://img.qammunity.org/2021/formulas/mathematics/high-school/gk3z9y02wex9li5oby9hqe33hz639p5czs.png)
![=(30+2x)*(12+2x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/x4gdt90hy7cedv89m7fky1i0fem6wq9mzz.png)
![(30+2x)*(12+2x)=1288](https://img.qammunity.org/2021/formulas/mathematics/high-school/kc769y9qemun3so69tffgtnx4zl783kji8.png)
![{x}^2+21x-232=0](https://img.qammunity.org/2021/formulas/mathematics/high-school/pbtogcl3ldqobury7pwdtgueel3sna2vzk.png)
solving equation we get
![x=8\text{ feet}](https://img.qammunity.org/2021/formulas/mathematics/high-school/oqcm5mh48rzbhc8m2wxsjias70m0ulu34e.png)
Hence the width of the path is
![8\text{ feet}](https://img.qammunity.org/2021/formulas/mathematics/high-school/48byzdx1sjvm7oxy284ajphh6b573i68a1.png)