Question

How many grams of magnesium chloride are produced when 650ml of 3 M hydroxide acid solution reacted with excess magnesium hydroxide solution?

Answer 1

`\large \boxed{\text{93 g Mg(OH)}_(2)}`

Step-by-step explanation:

We will need a balanced chemical equation with volumes, molar concentrations. and molar masses.

Mᵣ: 95.21

Mg(OH)₂ + 2HCl ⟶ MgCl₂ + 2H₂O

V/mL: 500 650

c/mol·L⁻¹: 3

1. Moles of HCl

`\text{Moles of HCl}=\text{0.650 L HCl} * \frac{\text{3 mol HCl}}{ \text{1 L HCl}} = \text{1.95 mol HCl}`

2. Moles of Mg(OH)₂

`\text{Moles of MgOH}_(2) =\text{1.95 mol HCl}* \frac{\text{1 mol Mg(OH)}_(2)}{\text{2 mol HCl}} =\text{0.975 mol MgOH}_(2)`

3. Mass of Mg(OH)₂

`c = \text{0.975 mol Mg(OH)}_(2) * \frac{\text{95.21 Mg(OH)}_(2)}{\text{1 mol Mg(OH)}_(2)} = \text{93 g Mg(OH)}_(2)\\\\\text{The reaction produces $\large \boxed{\textbf{93 g Mg(OH)}_(2)}$}`