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Factor completely 16x8 − 1.

(4x4 − 1)(4x4 + 1)
(2x2 − 1)(2x2 + 1)(4x4 + 1)
(2x2 − 1)(2x2 + 1)(2x2 + 1)(2x2 + 1)
(2x2 − 1)(2x2 + 1)(4x4 − 1)

2 Answers

4 votes

Given:

The given expression is

We need to determine the factor of the given expression.

Factor:

Let us rewrite the given expression.

Thus, we have;

Since, the above expression is of the form , let us apply the identity

Thus, we have;

------ (1)

Now, we shall factor the term

Substituting the above expression in equation (1), we have;

Therefore, the factor of the given expression is

Hence, Option B is the correct answer.

User Majusebetter
by
4.1k points
4 votes

Given:

The given expression is
16 x^(8)-1

We need to determine the factor of the given expression.

Factor:

Let us rewrite the given expression.

Thus, we have;


\left(4 x^(4)\right)^(2)-1^(2)

Since, the above expression is of the form
a^2-b^2, let us apply the identity
a^2-b^2=(a+b)(a-b)

Thus, we have;


\left(4 x^(4)+1\right)\left(4 x^(4)-1\right) ------ (1)

Now, we shall factor the term
4x^4-1


4x^4-1=(2x^2)^2-1^2


=(2x^2+1)(2x^2-1)

Substituting the above expression in equation (1), we have;


\left(4 x^(4)+1\right)\left(2 x^(2)+1\right)(2x^2-1)

Therefore, the factor of the given expression is
\left(4 x^(4)+1\right)\left(2 x^(2)+1\right)(2x^2-1)

Hence, Option B is the correct answer.

User Aryan Firouzian
by
4.0k points