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Find the equation of a line that is PERPENDICULAR to y = 1/3 x -2 & passes through the point ( 3, 2 ). (CHECK PIC FOR ANSWER CHOICES)

Find the equation of a line that is PERPENDICULAR to y = 1/3 x -2 & passes through-example-1
User JustDan
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1 Answer

3 votes

Answer:

The answer to your question is the letter b) y = -3x + 11

Explanation:

Data

Original line y = 1/3x - 2

Point = (3, 2)

New line = ? (perpendicular)

Process

1.- Get the slope of the original line

The slope is the coefficient of the x in the line equation.

y = 1/3x - 2

slope = m = 1/3

2.- Find the slope of the new line

new slope = -3 (because the lines are perpendicular)

3.- Find the equation of the new line

y - y1 = m(x - x1)

x1 = 3 y1 = 2

-Substitution

y - 2 = -3(x - 3)

-Simplification

y - 2 = -3x + 9

y = -3x + 9 + 2

-Result

y = -3x + 11

User Raphael Jeger
by
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