Question

Jonathan measured a line to be 14.5 inches long. If the actual length of the line is 14.7 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?

Answer 1

%Error = |14.5 - 14.7|/14.7 × 100% = 0.2/14.7 × 100%

%Error = 1.36 %

To the nearest tenth of the percent

%Error = 0%

Explanation:

Percentage error is used to determine how accurate a measurement is, it can be written mathematically as;

%Error = |measured - actual value|/actual value × 100%

Given;

Measured value = 14.5 inch

Actual value = 14.7 Inch

%Error = |14.5 - 14.7|/14.7 × 100% = 0.2/14.7 × 100%

%Error = 1.36 %

To the nearest tenth of the percent

%Error = 0%

Answer 2

1.4%

Explanation:

Actual Length = 14.7 inches

Wrong Measurement = 14,5 inches

Error in Measurement = 14.7 -14.5 =0.2 inches

Percentage Error = (Error in Measurement/Actual Value) X 100

=(0.2/14.7) X 100

=0.0136 X 100

=1.36%

Percentage Error=1.4% (to the nearest tenth)