109k views
0 votes
A particular deep-sea fish has a swim bladder that can hold a maximum to 0.34 L of gas. It lives at 500m depth. If the fish's swim bladder currently holds 0.12 L of gas, about how high could researchers safely raise it before rupturing ("popping") the swim bladder? (Show your work)

User Any
by
7.0k points

1 Answer

4 votes

Answer:

At the height of the 176 meter fish's swim bladder will hold the gas without rupturing its swim badder, at this height researchers can safely raise it.

Step-by-step explanation:

Pressure at depth of 500 m =
p_1=\rho* g* 500 m

Volume of gas hold by fish's swim bladder =
V_1=0.12 L

Pressure at dept h where fish's swim bladder can hold maximum gas =
P_2=\rho* g* h

Maximum volume of the gas in fish's swim bladder =
V_2=0.34 L

Applying Boyle's law:


P_1V_1=P_2V_2 ( at constant temperature)


\rho* g* 500 m* 0.12 L=\rho* g* h* 0.34 L


h=(\rho* g* 500 m* 0.12 L)/(\rho* g* 0.34 L)=176.5 m\approx 176 m

At the height of the 176 meter fish's swim bladder will hold the gas without rupturing its swim badder, at this height researchers can safely raise it.

User SomethingOn
by
7.1k points