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(5+(1)/(2) )(5-(1)/(2) )=(99)/(4)
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Explanation:

1. This term is called The Product of Sum and Difference of Two Binomials. What is this? You may ask. It means that you have two equal numbers being one positive and one negative in different parenthesis being multiplied by each other. Example;
(1+2)(1-2). 1 and 2 are in both parenthesis but with opposite signs. In your case, it's
(5+(1)/(2))(5-(1)/(2) ).

To solve this, simply take each number, square them, and put a negative sign in the middle.


(5)^2-((1)/(2))^2 = (99)/(4)

Solve;


(25)-((1)/(4))=(99)/(4)

Here you have an operation with fractions; remember that 25 has a 1 below it even though it is not shown. So in order to solve these, substract. I'm supposing you know how to do this, so I'm going straight to the answer.


(100-1)/(4)=(99)/(4)

Solve;


(99)/(4)=(99)/(4)

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