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The equation of line q is y = 1/3x-7Parallel to line q is liner, which passes through the

point (3, -9). What is the equation of liner?

User Mudit
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1 Answer

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Answer:


y = (1)/(3) x - 10

Explanation:

The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

Parallel lines have the same gradient. Hence the gradient of line r is
(1)/(3).

Susbt. m=
(1)/(3),


y = (1)/(3) x + c

To find c, substitute a coordinate.

When x=3, y= -9,


- 9 = (1)/(3) (3) + c

-9= 1 +c

c= -9-1

c= -10

Thus the equation of line r is
y = (1)/(3) x - 10.

User Krasimir Stoev
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