Question

Zn+2HCl=ZnCl2+H2 How many grams of ZnCl2 will be produced from 26.0 g of Zn and 42.0 g of HCl?

Answer 1

53.14 grams of Zn
`Cl_(2)` will be produced from 26.0 g of Zn and 42.0 g of HCl.

Step-by-step explanation:

Balanced chemical reaction:

Zn + 2 HCl ⇒ Zn
`Cl_(2)` +
`H_(2)`

data given:

mass of Zn = 26 grams

mass of HCl = 42 grams

mass of Zn
`Cl_(2)` = ?

here in the reaction Zn is the limiting reagent so mass of

Zn
`Cl_(2)` formed will be determined by it.

atomic mass of zinc =65.38 grams/mole

number of moles =
`(mass)/(atomic mass of 1 mole)`

putting the values in the above equation:

number of moles of zinc =
`(26)/(65.38)`

number of moles of zinc = 0.39 moles

From the balanced reaction it is seen that

1 mole of Zn produced 1 mole of Zn
`Cl_(2)`

0.39 moles will produce x moles of Zn
`Cl_(2)`

0.39 moles of Zn
`Cl_(2)` (atomic mass of Zn = 65.38 grams/mole)

mass = atomic mass x number of moles

= 0.39 x 136.28

= 53.14 grams

53.14 grams of Zn
`Cl_(2)` is formed