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I have no idea how to even begin this question.

Thank you!

I have no idea how to even begin this question. Thank you!-example-1

1 Answer

3 votes

Answer:

  • sin(x) = ±(√2)/2
  • r.a. = 45°
  • x = 45° +k·360°
  • x = 135° +k·360°
  • x = 225° +k·360°
  • x = 315° +k·360°
  • x ∈ {135°, 225°, 315°, 405°}

Explanation:

Start by solving for sin(x).

4sin(x)² = 2

sin(x)² = 1/2 . . . . divide by 4

sin(x) = ±√(1/2) = ±(√2)/2

Use your knowledge of the sine function to recognize that the reference angle is 45°, and that the angles x will be ...

x = ±45° or 180°±45° with multiples of 360° added

The solutions in the desired range are ...

x ∈ {135°, 225°, 315°, 405°}

User Martijn Brouwer
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