Question

When 435 J of heat is added to 3.4 g of olive oil at 2 C, the temperature

rises to 85 C. What is the specific heat of the oil?
1.54

10,619

17.8

122,757

Answer 1

(A) 1.54

Step-by-step explanation:

Given:

Heat, q = 435 J

Mass, m = 3.4 g

T₁ = 2°C

T₂ = 85°C

Specific heat, c = ?

We know:

q = mcΔT

where,

ΔT = T₂ - T₁

ΔT = (85°C - 2°C)

ΔT = 83°C

On substituting the value we get:

`435 = 3.4 X c X (83)\\\\c = (435)/(3.4 X 83) \\\\c = 1.54 J/g^oC`