Question

A company makes a cone-shaped container with a height of 15 in. The area of its base is about 78.8in.2 Approximately what is the volume of the container?

Answer 1

Approximately the volume of cone-shaped container is 393 in³.

Explanation:

Given:

A company makes a cone-shaped container with a height of 15 in.

The area of its base is about 78.8 in².

Now, to get the cone-shaped container volume.

So, we find the radius first by using formula:

Let the radius be
`r.`

(Using the value π = 3.14)

`A_(B)=78.8\ in^2.`

`A_(B)=\pi r^2`

`78.8=3.14* r^2`

Dividing both sides by 3.14 we get:

`25.09=r^2`

Using square root on both sides we get:

`5.00=r`

`r=5\ in.`

Thus, the radius (
`r`) = 5 in.

The height (
`h`) = 15 in.

Now, to get the volume of the cone-shaped container we put formula:

`Volume=\pi r^2(h)/(3)`

`Volume=3.14* 5^2* (15)/(3) \\\\Volume=3.14* 25* 5\\\\Volume=392.50\ in^3.`

Therefore, approximately the volume of the cone-shaped container is 393 in³.