A company makes a cone-shaped container with a height of 15 in. The area of its base is about 78.8in.2 Approximately what is the volume of the container?

Question

asked Mar 10, 2021 130k views

1 Answer

Pablo Grande · Answer 1 · 2021-03-15T04:14:11+0000

Answer:

Approximately the volume of cone-shaped container is 393 in³.

Explanation:

Given:

A company makes a cone-shaped container with a height of 15 in.

The area of its base is about 78.8 in².

Now, to get the cone-shaped container volume.

So, we find the radius first by using formula:

Let the radius be

(Using the value π = 3.14)

$A_(B)=78.8\ in^2.$

$A_(B)=\pi r^2$

78.8=3.14* r^2

Dividing both sides by 3.14 we get:

25.09=r^2

Using square root on both sides we get:

5.00=r

$r=5\ in.$

Thus, the radius (
) = 5 in.

The height (
) = 15 in.

Now, to get the volume of the cone-shaped container we put formula:

$Volume=\pi r^2(h)/(3)$

$Volume=3.14* 5^2* (15)/(3) \\\\Volume=3.14* 25* 5\\\\Volume=392.50\ in^3.$

Therefore, approximately the volume of the cone-shaped container is 393 in³.