Question

A 80-kg person running at 5 m/s is pushed by the wind for 20 seconds so that their velocity increases to 6 m/s. How much force does the wind apply to the runner

Answer 1

The force applied by the wind to the runner is 4 N.

Step-by-step explanation:

Given that,

Mass of the person, m = 50 kg

Initial speed, u = 5 m/s

Final speed, v = 6 m/s

Time, t = 20 s

We need to find the force applied by the wind to the runner. It is based on Newton's second law of motion. The force is given by :

`F=m* a\\\\F=(m(v-u))/(t)\\\\F=(80* (6-5))/(20)\\\\F=4\ N`

So, the force applied by the wind to the runner is 4 N.