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How many grams of oxygen are needed to complete the combustion of 8 g of methane, CH4
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How many grams of oxygen are needed to complete the combustion of 8 g of methane, CH4

User MohyG
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5 votes

Answer:

32 grams

Step-by-step explanation:

So 1 mole of methane requires 2 moles of oxygen for complete combustion. So 16 g of Methane requires 64 g of oxygen for the complete combustion.

So 8 g of Methane requires = 8x64/16=32 g of oxygen.

User Aldana
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