Answer:
15 cm by 12 cm.
Explanation:
Given:
Amanda uses a rectangular canvas for a panting.
The length is
centimeters.
The width is
centimeters, and is 4/5 of the length .
Question asked:
.What are the dimensions of the canvas ?
Solution:
As given that the width is
of the length.
![2x+6=(4)/(5) (6x-3)\\ \\ 2x+6=(4)/(5)*6x-(4)/(5)*3\\ \\ 2x+6=(24x)/(5) -(12)/(5) \\ \\](https://img.qammunity.org/2021/formulas/mathematics/high-school/rloqbl8q9uvjs3pv7coq1xbgwzv7v3b66b.png)
Adding both sides by
![(12)/(5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/g0y47pl6fwbq2shorp650a0g9i8b488zz0.png)
![2x+6+(12)/(5) =(24x)/(5) -(12)/(5)+(12)/(5)\\ \\ 2x+(42)/(5) =(24x)/(5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/7iiz1tyxyxqr1ukehylsxy5atie7a2qxfc.png)
Subtracting both sides by
![2x](https://img.qammunity.org/2021/formulas/mathematics/middle-school/cyg7d2oalz2m0jqsj2hy58xor26uts979u.png)
![2x-2x+(42)/(5) =(24x)/(5) -2x\\ \\ (42)/(5) =(24x-10x)/(5) \\ \\ (42)/(5) =(14x)/(5) \\ \\](https://img.qammunity.org/2021/formulas/mathematics/high-school/hmgwa0drvdp5anhibxdjeloxfd7vke2wh3.png)
By cross multiplication:-
![5*14x=5*42\\ \\ 70x=210\\ \\](https://img.qammunity.org/2021/formulas/mathematics/high-school/77px3ocp4nuhsot8by03iff6293bblbqur.png)
By diving both sides by 70
![x=3](https://img.qammunity.org/2021/formulas/mathematics/college/yzekanmiuar9edsve93wg5dpqbw3650n5b.png)
Now, substituting the value:-
The length =
cm
=
![6*3-3=18-3=15\ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/etfaekz7fa76o8euok5p1p3m4o7g6xjzov.png)
The width =
cm
=
![2*3+6=6+6=12\ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/j490yj1whna8usq5sf4zmjin7mcxd1cf7o.png)
Thus, length and width of canvas are 15 cm and 12 cm.