Question

Two charges, and , are separated by a certain distance R. If the magnitudes of the charges are doubled and their separation is also doubled, then what happens to the electrical force between these two charges?

Answer 1

The electrical force between the given charges remains the same.

Step-by-step explanation:

The expression for the electrical force is as follows as;

`F=(kq_(1)q_(2))/(R^(2))`

Here, k is the constant,
`q_(1),q_(2)` are the charges, F is the electrical force and R is the distance between the charges.

It is given in the problem that the magnitudes of the charges and the magnitudes of the separation between the charges are doubled.

Then, the expression of the electrical force becomes as;

`F'=(k(2q_(1))(2q_(2)))/((2R)^(2))`

`F'=(k4q_(1)q_(2))/(4R^(2))`

`F'=(kq_(1)q_(2))/(R^(2))`

`F'=F`

Therefore, the electrical force between the given charges remains the same.