Answer:
a) n = 235
p = 0.03
b) P(X=12) = 0.02655
c) P(X ≤ 12) = 0.9737
d) Mean = μ = 7.05 stolen bicycles would be returned.
This means that for the 235 stolen bicycles in the year under review, 7.05 of them are expected to be returned.
e) Standard deviation = σ = 2.62 returned bicycles.
Explanation:
Binomial Distribution problems are solved with the Binomial distribution function.
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = number of stolen bicycles = 235
x = Number of successes required = variable; depending on the question
p = probability of success = Probability of a bike being returned = 3% = 0.03
q = probability of failure = Probability of a bike not being returned = 1 - 0.03 = 0.97
a) The fixed number of trials = number of stolen bikes in a year under review = n = 235
p = success probability = Probability of a bike being returned = 3% = 0.03
b) The probability that exactly 12 of the stolen bicycles are returned to their owners
P(X=12)
n = 235, p = 0.03, q = 0.97, x = 12
P(X=12) = ²³⁵C₁₂ (0.03)¹² (0.97)²³⁵⁻¹²
P(X=12) = 0.0265471215 = 0.02655
c) The probability that at most 12 of the stolen bicycles are returned to their owners. P(X ≤ 12)
P(X ≤ 12) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5) + P(X=6) + P(X=7) + P(X=8) + P(X=9) + P(X=10) + P(X=11) + P(X=12)
Solving each of these and summing them all up or using the Binomial distribution calculator,
P(X ≤ 12) = 0.97368510024 = 0.9737
d) Mean for Binomial distribution is given as
Mean = np = (235)(0.03) = 7.05 stolen bicycles would be returned.
This is the number of stolen bicycles that would be returned.
This means that for the 235 stolen bicycles in the year under review, 7.05 of them are expected to be returned.
e) Standard deviation for Binomial distribution is given as
σ = √[np(1-p)] = √(235×0.03×0.97) = 2.615 ≈ 2.62 returned bicycles.
Hope this Helps!!!!