Answer:
The fraction of smoothies sold were either banana or strawberry is
![(11)/(12).](https://img.qammunity.org/2021/formulas/mathematics/high-school/fntaxm4g928r3p0unyje4pobdimvez0keh.png)
Explanation:
Given:
Of the smoothies sold yesterday at Marlins smoothie shop, 5/6 were banana and another 1/12 were strawberry.
Now, to find the fraction of the smoothies sold were either banana or strawberry.
Fraction of smoothie were of banana =
![(5)/(6) .](https://img.qammunity.org/2021/formulas/mathematics/high-school/ojdxbrzk9i10udd9ckphln3jq12xe7og87.png)
Fraction of smoothie were of strawberry =
![(1)/(12) .](https://img.qammunity.org/2021/formulas/mathematics/high-school/hv013norg52rp6x59sheptp7wg5y0smdlm.png)
Now, to get the fraction smoothies sold were either banana or strawberry by adding both the fractions of banana and strawberry:
![(5)/(6) +(1)/(12) \\\\=(10+1)/(12) \\\\=(11)/(12)](https://img.qammunity.org/2021/formulas/mathematics/high-school/dzzc04klmub3bbecft3ftra5mz1hczf1wy.png)
Therefore, the fraction of smoothies sold were either banana or strawberry is
![(11)/(12).](https://img.qammunity.org/2021/formulas/mathematics/high-school/fntaxm4g928r3p0unyje4pobdimvez0keh.png)