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If a bug can flap its wings at a rate of 60 times in 2 seconds, how many times do they flap their wings in 2.604 minutes? Round to 1 decimal.

1 Answer

5 votes

Answer:

4,687.2 flaps

Explanation:

#We calculate the number of flaps per second:


Flaps/Second=(60)/(2)\\\\=30 \ flaps

#Since one minute has 60 seconds, we will multiply our time by 60 seconds and then by flaps/second:


Flaps=Rate * time\\\\=30* 2.604* 60\\\\=4687.2\ flaps

Hence, the bird makes 4,687.2 flaps in 2.604 minutes.

User Marnix Harderwijk
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