Question

A polynomial f of degree 3 that has zeros at -1 and 2 and has f(0) =3

Answer 1

f(x) = (x+1)(x-2)(x-3/2)

Explanation:

hello :

an polynomial f of degree 3 is : f(x) = (x+1)(x-2)(x-a)

f(0) =3 means : (0+1)(0-2)(0-a) =3

so : 2a=3 a=3/2

f(x) = (x+1)(x-2)(x-3/2)