Question

A uniform steel rod has mass 0.400 kg and length 50.0 cm and is horizontal. A uniform sphere with radius

10.00 cm and mass 0.800 kg is welded to one end of the bar, and a uniform sphere with radius 5.00 cm
and mass 0.200 kg is welded to the other end of the bar. The centers of the rod and of each sphere all lie
along a horizontal line. How far is the center of gravity of the combined object from the center of the rod?

Answer 1

goofy ahh

Step-by-step explanation:

do ur own work

Answer 2

Step-by-step explanation:

Center of gravity , Let center of rod is origin

=
`((0.400*0)+(0.800*(50)/(2)+10)+ (0.200 *(-(25+5)) )/(0.400+0.800+0.200)`

=15.71cm from the center of rod