Question

A cylinder of argon gas contains 50.0 L of Ar at 18.4 atm and 127 °C. How many moles of argon is in the cylinder?

Answer 1

n=28.03

Step-by-step explanation:

For this problem you would have to use the Ideal gas law formula which is
`PV=nRT`. In this formula, R is called the ideal gas law constant which is R= 0.08205

For your problem, this formula would look like this...
`n=(PV)/(RT)`

First you would have to convert Celsius to Kelvin: 273 + 127 C= 400K

Your problem would look like this in the formula
`n= ((18.4 atm)(50.0 L))/((0.08205)(400 K))`

Once solved n= 28.03 mol