Question

What is the equation for the hyperbola shown?

x^2/60^2-y^2/11^2=1

x^2/11^2-y^2/60^2=1

y^2/60^2-x^2/11^2=1

y^2/11^2-x^2/60^2=1

Answer 1

Option 1

Explanation:

(x - 0)²/60² - (y - 0)²/11² = 1

x²/60² - y²/11² = 1

Answer 2

The answer to your question is
`(x^(2))/(60^(2)) - (y^(2))/(11^(2)) = 1`

Explanation:

Data

From the graph

Horizontal hyperbola

Center (0, 0)

a = 60 a is the distance from the Center to the Vertex

b = 11 b is the distance from the Center to the endpoint of the conjugate

axis.

The Equation for a horizontal hyperbola

`((x- h)^(2) )/(a^(2)) - ((y - k)^(2))/(b^(2)) = 1`

h = 0, k = 0

-Substitution

`(x^(2))/(60^(2)) - (y^(2))/(11^(2)) = 1`